(c+3)(c^2-3c+5)=

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Solution for (c+3)(c^2-3c+5)= equation:


Simplifying
(c + 3)(c2 + -3c + 5) = 0

Reorder the terms:
(3 + c)(c2 + -3c + 5) = 0

Reorder the terms:
(3 + c)(5 + -3c + c2) = 0

Multiply (3 + c) * (5 + -3c + c2)
(3(5 + -3c + c2) + c(5 + -3c + c2)) = 0
((5 * 3 + -3c * 3 + c2 * 3) + c(5 + -3c + c2)) = 0
((15 + -9c + 3c2) + c(5 + -3c + c2)) = 0
(15 + -9c + 3c2 + (5 * c + -3c * c + c2 * c)) = 0
(15 + -9c + 3c2 + (5c + -3c2 + c3)) = 0

Reorder the terms:
(15 + -9c + 5c + 3c2 + -3c2 + c3) = 0

Combine like terms: -9c + 5c = -4c
(15 + -4c + 3c2 + -3c2 + c3) = 0

Combine like terms: 3c2 + -3c2 = 0
(15 + -4c + 0 + c3) = 0
(15 + -4c + c3) = 0

Solving
15 + -4c + c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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